// The donut code with fixed-point arithmetic; no sines, cosines, square roots, or anything.
// a1k0n 2020
// Code from: https://gist.github.com/a1k0n/80f48aa8911fffd805316b8ba8f48e83
// For more info:
// - https://www.a1k0n.net/2011/07/20/donut-math.html
// - https://www.youtube.com/watch?v=DEqXNfs_HhY

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#include <libbase/console.h>

#define R(mul,shift,x,y) \
  _=x; \
  x -= mul*y>>shift; \
  y += mul*_>>shift; \
  _ = (3145728-x*x-y*y)>>11; \
  x = x*_>>10; \
  y = y*_>>10;

signed char b[1760], z[1760];

void donut(void) {
  int sA=1024,cA=0,sB=1024,cB=0,_;
  for (;;) {
    memset(b, 32, 1760);  // text buffer
    memset(z, 127, 1760);   // z buffer
    int sj=0, cj=1024;
    for (int j = 0; j < 90; j++) {
      int si = 0, ci = 1024;  // sine and cosine of angle i
      for (int i = 0; i < 324; i++) {
        int R1 = 1, R2 = 2048, K2 = 5120*1024;

        int x0 = R1*cj + R2,
            x1 = ci*x0 >> 10,
            x2 = cA*sj >> 10,
            x3 = si*x0 >> 10,
            x4 = R1*x2 - (sA*x3 >> 10),
            x5 = sA*sj >> 10,
            x6 = K2 + R1*1024*x5 + cA*x3,
            x7 = cj*si >> 10,
            x = 40 + 30*(cB*x1 - sB*x4)/x6,
            y = 12 + 15*(cB*x4 + sB*x1)/x6,
            N = (((-cA*x7 - cB*((-sA*x7>>10) + x2) - ci*(cj*sB >> 10)) >> 10) - x5) >> 7;

        int o = x + 80 * y;
        signed char zz = (x6-K2)>>15;
        if (22 > y && y > 0 && x > 0 && 80 > x && zz < z[o]) {
          z[o] = zz;
          b[o] = ".,-~:;=!*#$@"[N > 0 ? N : 0];
        }
        R(5, 8, ci, si)  // rotate i
      }
      R(9, 7, cj, sj)  // rotate j
    }
    for (int k = 0; 1761 > k; k++)
      putchar(k % 80 ? b[k] : 10);
    R(5, 7, cA, sA);
    R(5, 8, cB, sB);
  	if (readchar_nonblock()) {
  		getchar();
  		break;
  	}
    fputs("\x1b[23A", stdout);
  }
}